IBM C9050-042 Q&A - in .pdf

  • Exam Code: C9050-042
  • Exam Name: Developing with IBM Enterprise PL/I
  • Updated: Sep 01, 2026
  • Q & A: 140 Questions and Answers
  • Printable IBM C9050-042 PDF Format. It is an electronic file format regardless of the operating system platform.
  • PDF Price: $59.99
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IBM C9050-042 Q&A - Testing Engine

  • Exam Code: C9050-042
  • Exam Name: Developing with IBM Enterprise PL/I
  • Updated: Sep 01, 2026
  • Q & A: 140 Questions and Answers
  • Install on multiple computers for self-paced, at-your-convenience training.
  • PC Test Engine Price: $59.99
  • Testing Engine

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IBM C9050-042 Exam Syllabus Topics:

SectionObjectives
Program Structure and Control- Control Flow
  • 1. Conditional statements
  • 2. Iterative processing
  • 3. Branching and exception handling
- Procedures and Blocks
  • 1. Scope and declarations
  • 2. Parameter passing
  • 3. Main and subprocedures
PL/I Language Fundamentals- Expressions and Operators
  • 1. Arithmetic expressions
  • 2. String operations
  • 3. Logical and relational operators
- Data Types and Declarations
  • 1. Scalar and aggregate data
  • 2. Initialization and constants
  • 3. Attributes and storage classes
IBM Enterprise PL/I Features- Integration Technologies
  • 1. Interoperability with C and Java
  • 2. XML support
  • 3. JSON support
- Compiler and Runtime Features
  • 1. Optimization and diagnostics
  • 2. Debugging techniques
  • 3. Compiler options
File and I/O Processing- Input and Output Formatting
  • 1. Formatting data
  • 2. GET and PUT statements
- File Operations
  • 1. OPEN, READ, WRITE, and CLOSE statements
  • 2. Record processing
  • 3. Sequential and direct access files
Data Processing- Character and String Handling
  • 1. Substring processing
  • 2. Built-in string functions
  • 3. Pattern and conversion operations
- Arrays and Structures
  • 1. Based and controlled storage
  • 2. Structure definitions
  • 3. Array manipulation

IBM Developing with IBM Enterprise PL/I Sample Questions:

Question 1

Which of the following is the most likely reason to use a debugger in a production environment?

A. Enhance performance
B. Ensure data integrity
C. Test a program
D. Investigate error situations


Question 2

Requirement:
The function LEAPYEAR evaluates a given 4-digit number and returns '1'B if it is a leap year, '0'B if it is
not. This function is supposed to work for the years 2004 to 2015.
Leap years occur every four years, except for years ending in 00 that are not divisible by 400. Which of
the following solutions meets the requirement and does NOT need to be changed if the requirement
changes to: The function is supposed to work for the years 1900 to 3000.

A. LEAPYEAR: PROC(YEAR) RETURNS(BIT(1));
DCL YEAR PlC '9999';
DCL (MOD,VERIFY) BUILTIN;
SELECT;
WHEN (VERIFY(YEAR,'0l23456789') ^= 0) RETURN('0'B);
WHEN (MOD(YEAR,100) = 0)RETURN('0'B);
WHEN (MOD(YEAR,4) = 0)RETURN('1'B);
OTHERRETURN('0'B);
END;
END LEAPYEAR;
B. LEAPYEAR:PROC(YEAR) RETURNS(BIT(1));
DCL YEAR PlC '9999';
DCL (MOD,VERIFY) BUILTIN;
SELECT;
WHEN (VERIFY(YEAR '0123456769') ^= 0) RETURN('0'B); WHEN (MOD(YEAR,100) = 0)
RETURN('0'B);
WHEN (MOD(YEAR,400) = 0) RETURN('1'B);
WHEN (MOD(YEAR,4) = 0) RETURN('1'B);
OTHERRETURN('0'B);
END;
END LEAPYEAR;
C. LEAPYEAR:PROC(YEAR) RETURNS(BIT(1));
DCL YEAR PlC '9999';
DCL (MOD,VERIFY) BUILTIN;
SELECT;
WHEN (VERIFY(YEAR '0123456789') ^= 0) RETURN('0'B);
WHEN (MOD(YEAR,400) = 0) RETURN('l'B); WHEN (MOD(YEAR,100) = 0) RETURN('0'B);
WHEN (MOD(YEAR,4) = 0) RETURN('1'B); OTHER RETURN('0'B);
END;
END LEAPYEAR;
D. LEAPYEAR: PROC(YEAR) RETURNS(BIT(1));
DCL YEAR PlC '9999';
DCL VERIFY BUILTIN;
IFVERIFY(YEAR,0123456789)^= 0 THEN RETURN('0'B);
SELECT(YEAR);
WHEN (2004) RETURN('1'B);
WHEN (2008) RETURN('1'B);
WHEN (2012) RETURN('1'B);
OTHER RETURN('0'B);
END;
END LEAPYEAR;


Question 3

Prerequisite:
A sorted input dataset with record length 100 contains at least one record for each of the values '1', '2', '3'
in the first byte. The applied sort criteria is 1,100,ch,a.
Requirements:
1 .) All records with '1' in the first byte must be ignored.
2 .) All records with '2' in the first byte must be written to the output dataset.
3 .) If there is a '3' in the first byte, the read iteration must be left.
4 .) The program must not abend or loop infinitely.
If the code below does not fulfill the specifications provided above, which of the following is the most likely
reason?
DCL DDIN FILE RECORD INPUT;
DCL DDOUT FILE RECORD OUTPUT;
DCL 1 INSTRUC,
3 A CHAR(1),
3 * CHAR(99);
DCL EOF_IN BIT(1) INIT('0'B);
DCL (Z1,Z2,Z3,ZO) BIN FIXED(31) INIT(0);
ON ENDFILE(DDIN) EOF_IN = '1'B;
READ FILE(DDIN) INTO (INSTRUC);
LOOP: DO WHILE (^EOF_IN);
SELECT(INSTRUC.A);
WHEN('1') DO;
Z1 +-= Z1;
ITERATE LOOP;
END;
WHEN('3') DO;
Z3 = Z3+1;
LEAVE LOOP;
END;
WHEN('2') DO;
Z2 = Z2+1;
WRITE FILE(DDOUT) FROM(INSTRUC);
END;
OTHER DO;
ZO = ZO+1;
PUT SKIP LIST(INSTRUC.A);
END;
END;/*select*/
READ FILE(DDIN) INTO(INSTRUC);
END ;/*loop*/

A. The code does not fulfill the requirement because not all records with '2' in the first byte will be written to the output dataset.
B. The code fulfills the requirement.
C. The code does not fulfill the requirement because the last record with '2' in the first byte will be written twice to the output dataset.
D. The code does not fulfill the requirement because the program will loop infinitely.


Question 4

Which software quality describes the ability of software to cooperate with other applications?

A. Portability
B. Reusability
C. Interoperability
D. Scalability


Question 5

Given the following pseudocode example, at which label should an unconditional COMMIT be placed
assuming there is a one-to-many relationship between FIL01 and FIL02 and FlL01 contains several
thousand records?
Read record from file FIL01
1 . DO while there are records in FIL01 IF record in FIL01 specifies update THEN DO for all records
matching in FIL02 Update record in FIL02 with information from FIL01 end DO
2 . end IF
3 . Read next record in FIL01
4 . end DO

A. 4
B. 3
C. 2
D. 1


Solutions:

Question 1
Answer: D
Question 2
Answer: C
Question 3
Answer: D
Question 4
Answer: C
Question 5
Answer: C

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